#include<iostream.h>
#include<conio.h>
using namespace std;
int min(int a, int b);
int cost[10][10], a[10][10], i, j, k, c;
int min(int a, int b)
{
if (a < b)
return a;
else
return b;
}
int main(int argc, char **argv)
{
int n, m;
cout << "Enter no of vertices";
cin >> n;
cout << "Enter no of edges";
cin >> m;
cout << "Enter the\nEDGE Cost\n";
for (k = 1; k <= m; k++)
{
cin >> i >> j >> c;
a[i][j] = cost[i][j] = c;
}
for (i = 1; i <= n; i++)
for (j = 1; j <= n; j++)
{
if (a[i][j] == 0 && i != j)
a[i][j] = 31999;
}
for (k = 1; k <= n; k++)
for (i = 1; i <= n; i++)
for (j = 1; j <= n; j++)
a[i][j] = min(a[i][j], a[i][k] + a[k][j]);
cout << "Resultant adj matrix\n";
for (i = 1; i <= n; i++)
{
for (j = 1; j <= n; j++)
{
if (a[i][j] != 31999)
cout << a[i][j] << " ";
}
cout << "\n";
}
return 0;
}
OUTPUT
Enter no of vertices 3
Enter no of edges 5
Enter the
EDGE Cost
1 2 4
2 1 6
1 3 11
3 1 3
2 3 2
Resultant adj matrix
0 4 6
5 0 2
3 7 0
#include<conio.h>
using namespace std;
int min(int a, int b);
int cost[10][10], a[10][10], i, j, k, c;
int min(int a, int b)
{
if (a < b)
return a;
else
return b;
}
int main(int argc, char **argv)
{
int n, m;
cout << "Enter no of vertices";
cin >> n;
cout << "Enter no of edges";
cin >> m;
cout << "Enter the\nEDGE Cost\n";
for (k = 1; k <= m; k++)
{
cin >> i >> j >> c;
a[i][j] = cost[i][j] = c;
}
for (i = 1; i <= n; i++)
for (j = 1; j <= n; j++)
{
if (a[i][j] == 0 && i != j)
a[i][j] = 31999;
}
for (k = 1; k <= n; k++)
for (i = 1; i <= n; i++)
for (j = 1; j <= n; j++)
a[i][j] = min(a[i][j], a[i][k] + a[k][j]);
cout << "Resultant adj matrix\n";
for (i = 1; i <= n; i++)
{
for (j = 1; j <= n; j++)
{
if (a[i][j] != 31999)
cout << a[i][j] << " ";
}
cout << "\n";
}
return 0;
}
OUTPUT
Enter no of vertices 3
Enter no of edges 5
Enter the
EDGE Cost
1 2 4
2 1 6
1 3 11
3 1 3
2 3 2
Resultant adj matrix
0 4 6
5 0 2
3 7 0
I dont think this code is fast and efficient enough. Thanks for sharing anyways =)
ReplyDeleteThis is floyd warshall not johnson's algorithm
ReplyDelete